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### Topic: Molar mass from boiling point and Kb...  (Read 9448 times)

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#### Zoloft

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##### Molar mass from boiling point and Kb...
« on: March 02, 2009, 09:38:45 AM »
Hey all, I'm slightly stuck on how to go about solving this.

"A solution prepared from 1.25 g of wintergreen (methyl salicylate) in 99.0 g benzene has a boiling point of 80.31 C. What is the molar mass of wintergreen? Boiling point of pure benzene is 80.10 C. Kb for benzene is 2.53C/m "

I know the answer is 152.12 g/mol of wintergreen, but I do not know how this answer was produced. Any directions or hints would be appreciated.

« Last Edit: March 02, 2009, 09:54:08 AM by thesloc »

#### Zoloft

• Regular Member
• Posts: 29
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##### Re: Molar mass from boiling point and Kb...
« Reply #1 on: March 02, 2009, 09:51:57 AM »
Never mind, I solved this.

:delta: Tb / kb = m

^my starting equation...and just solve for grams granted that molality is mol of methyl divided by Kg of benzene (solvent)