[timchai]

CH3CH2OCH3+HI---->? , i think it can be either CH3CH2I+CH3OH or CH3I+CH3CH2OH (both or either one

[cliverlong]

CH3CH2OCH3+HI---->? , i think it can be either CH3CH2I+CH3OH or CH3I+CH3CH2OH (both or either one

Does the following help?

http://www.cem.msu.edu/~reusch/VirtualText/alcohol2.htm

see section  on "3. Reactions of Ethers"

Can you write meaningful titles to your posts rather than continually putting

chem(plz help me bcoz i am very silly


Also deliberately using incorrect "text spelling" such as "bcoz" and "plz" and calling yourself "silly" isn't charming nor endearing, it just makes you look very foolish.

Clive

[AWK]

Depending on condition of your reaction you can reduce acetone with HI  to
2-propanol, then exchange OH group for I, and even reduce 2-iodopropane to propane.
Note - iodine formed during reduction can also react with acetone.

[cliverlong]

Depending on condition of your reaction you can reduce acetone with HI  to
2-propanol, then exchange OH group for I, and even reduce 2-iodopropane to propane.
Note - iodine formed during reduction can also react with acetone.

The formula given is

CH3CH2OCH3

is this not an ether?

I see where you are coming from AWK. If the formula was CH3CH2COCH3 then this would be a ketone. If the terminal group was carbonyl then this would be an aldehyde (such as acetone / ethanone)
http://en.wikipedia.org/wiki/Ketone
http://en.wikipedia.org/wiki/Aldehyde

Tim,

Can you check your formula?

Clive

[AWK]

Sorry, I did not notice this difference. Of course ethers can be broken by HI. Usually more volatile iodide and alcohol is formed at proper conditions, but alcohol can be furher reduced to hydrocarbon through iodide.
This reaction is commonly use for synthesis of phenols from its methyl ethers since  no phenyl iodide is formed in the course of reaction