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Topic: Need a little bit of help REDOX  (Read 3095 times)

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Offline Zapper

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Need a little bit of help REDOX
« on: March 03, 2009, 04:57:21 PM »
How do i write the products of three reactants  for a redox equation?

KMnO4(-) + NaHSO3(-) + H2SO4 => ?

Please help me understand how to write it and why it works that way.
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Offline Arkcon

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Re: Need a little bit of help REDOX
« Reply #1 on: March 03, 2009, 06:27:29 PM »
Well, to help you try to figure it out on your own, since you've been told this is a Red-Ox reaction, can you take a stab at what is reduced, and what is oxidized?  It's a little daunting, at first, doing it that way, but you'll be better off at exam time.
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Offline Zapper

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Re: Need a little bit of help REDOX
« Reply #2 on: March 03, 2009, 08:31:00 PM »
I think i figured it out

2(5e(-)+ 8H(+) + MnO4(-) >> Mn(+2) + 4H2O)
5(H2O + HSO3(-) >> SO4(-2) + 3H(+) + 2e(-))

= 2MnO4(-) + 5HSO3(-) + 8H(+) >> 5SO4(-2) + 2MN(+2) + 3H2O
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Offline Borek

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Re: Need a little bit of help REDOX
« Reply #3 on: March 04, 2009, 03:24:25 AM »
Check hydrogen.
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