Topic: Why filter a Nearly Saturated Solution of Ca(OH)2 (Read 4837 times)

oiewhgoiewh · « **on:** March 03, 2009, 08:45:00 PM »

From a lab I am about to do:

"Pour 25.0 mL of nearly saturated solution of Ca(OH)2 into filter paper"

I am wondering why I would need to filter the solution (what a filter paper would capture). Isn't filter paper just good for removing solids. It is not even expected that all solution will pass through, only 15-20 mL. Why?

nj_bartel · « **Reply #1 on:** March 03, 2009, 11:46:09 PM »

Are you sure it's not to wet the filter paper, in order to get it to adhere to the buchner/hirsch funnel better?

macman104 · « **Reply #2 on:** March 03, 2009, 11:54:38 PM »

Can you give us the whole procedure? What context is that question in regards to?

First thought is that maybe you are washing a solid that is already there with this basic solution? Maybe to remove an impurity?

AWK · « **Reply #3 on:** March 04, 2009, 12:51:30 AM »

Ca(OH)2 easily reacts with carbon dioxide from air to form insoluble CaCO₃

macman104 · « **Reply #4 on:** March 04, 2009, 07:31:18 PM »

Quote from: AWK on March 04, 2009, 12:51:30 AM

Ca(OH)2 easily reacts with carbon dioxide from air to form insoluble CaCO₃

Ah, so filtering to remove these insoluble impurities?

Topic: Why filter a Nearly Saturated Solution of Ca(OH)2 (Read 4837 times)

oiewhgoiewh

Why filter a Nearly Saturated Solution of Ca(OH)2

nj_bartel

Re: Why filter a Nearly Saturated Solution of Ca(OH)2

macman104

Re: Why filter a Nearly Saturated Solution of Ca(OH)2

AWK

Re: Why filter a Nearly Saturated Solution of Ca(OH)2

macman104

Re: Why filter a Nearly Saturated Solution of Ca(OH)2

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