Hey Guys, I need help with this question>

When 10.0 L of a saturated solution of magnesium carbonate, MgCO_{3} , is evaporated to dryness, 0.012g of solid magnesium carbonate is obtained. Calculate the Ksp of magnesium carbonate.

Ok, I've tried everything, and I still could not get the answer (it is 2.0 x 10^{-10}) .

This is what I've done.

The equation I made is : MgCO_{3} <---> Mg ^{2+} + CO_{3}^{2-}

1.00g MgCO_{3} x 1 mol MgCO_{3} / 84.3 g/mol = 0.01168 M / 10 L = 1.87 x 10^{-3}

Ice Table:

I (ignored) 0 0

C (ignored) + x +x

E 1.86 x 10^{-3} +x +x

Ksp = [Mg][CO_{3}]

I Have no idea what to do next :/ , how can I get the Ksp I am stuck.