Equal masses (.500 g each) of H2 and O2 are placed in an evacuated 4.00 L flask at 25.0 C. The mixture is allowed to react to completion and the flask is retunred to 25.0 C and allowed to come to equilibrium. The equilibrium vapor pressure of water at 25.0 C is 23.76 torr.
a. Write and balance an equation for the reaction.
2 H2 + O2 <==> 2 H2O
b. What is the total pressure inside the flask before the reaction begins?
.5g H2 / 2.02g H2 = .248 mol H2
.5g O2 / 32g O2 = .0156 mol O2
PV = nRT
P = (.2636mol * 62.4 * 298K) / 4L = 1230 torr
c. What is the mass of water vapor in the flask at equilibrium?
PV = nRT
I used the equilibrium vapor pressure of water as P, but I'm not sure if this is correct
(23.76 torr)(4L) = n(62.4)(298K)
n = .00511 mol H2O
.00511 mol H2O*18.02g = .0921g of water
d. How many gras of which reactant gas remains at equilibrium?
I did a limiting reactant problem, and I found that H2 is left over.
Since .00511 mol of H2 is used in the equilibrium process, so .243 mol remains at equilibrium? [I'm not sure about this answer at all]
e. What is the total pressure inside the flask at equilibrium?
f. After the reaction, is there any liquid water present? If so, how many grams? If not, why not?