If one starts with pure NO2(g) at a pressure of 0.500 atm, the total pressure inside the reaction vessel when 2NO2(g) →2NO(g) + O2(g) reaches equilibrium is 0.674 atm. Calculate the equilibrium partial pressure of NO2.
Choose one answer.
a. 0.152 atm
b. 0.174 atm
c. 0.200 atm
d. 0.326 atm
e. The total pressure cannot be calculated because Kp is not given
I'm having a hard time setting this up.
2NO2 2NO O2
I .500 0 0
C -x +x +x
E .500-x 2X x
P total= .674=P2NO2 + P2NO + PO2
?this doesn't come out right....