April 18, 2024, 01:59:29 PM
Forum Rules: Read This Before Posting


Topic: Calculating Equlibrium concentrations  (Read 2836 times)

0 Members and 1 Guest are viewing this topic.

Offline Kingjim9

  • New Member
  • **
  • Posts: 7
  • Mole Snacks: +0/-0
Calculating Equlibrium concentrations
« on: March 17, 2009, 06:05:06 PM »
Hi, I was hoping someone could help me with this one question I can't seem to figure out:

Quote
Equal volumes of 0.12M AgNO3 and 0.14M ZnCl2 solution are mixed.  Calculate the equilibrium concentrations of Ag+, Cl-, Zn2+, and NO3-

I started it off by calculating the moles of AgNO3 to be .07 mol (.12M * .5L = .06) Assuming there was half a liter of each to make 1 liter of solution total.
I got moles of ZnCl2 the same wayand got .07 moles.

Then I set up my reaction:  Ag(NO3) + ZnCl2 ::equil:: AgCl2 + Zn(NO3)

I tried setting up an I.C.E. table to try to figure out the equilibrium concentrations but i can't seem to get any farther than that point.  That is all the information i'm given about the problem and I don't know any kind of Ksp or anything.

Any Help will be appreciated,

Thanks,

Jim

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27652
  • Mole Snacks: +1800/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Calculating Equlibrium concentrations
« Reply #1 on: March 17, 2009, 06:25:28 PM »
Try to do it as a limiting reagent question.

In general you should also account for AgCl Ksp, but seems like AgCl can be treated (in the presence of excess of one reactants) as completely insoluble.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links