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Topic: Mass Balance: X2Y3  (Read 7994 times)

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Offline interminable

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Mass Balance: X2Y3
« on: March 21, 2009, 08:10:31 PM »
Consider the dissolution of the compound X2Y3, which gives X2Y22+, X2Y4+, X2Y3(aq), and Y2-. Use the mass balance to find an expression for [Y2-] in terms of the other concentrations. Simplify your answer as much as possible.

This is just a problem I'm doing for practice, so I have the answer, but I don't follow it.

Y total = (3/2)(X total)
I understand this. But the next step I do not follow:

2[X2Y22+] + [X2Y4+] + 3[X2Y3] + [Y2-] = 3/2{2[X2Y22+] + 2[X2Y4+] + 2[X2Y3]}

Where did all the coefficients of 2 and 3 come from??

Final Answer
[Y2-] = [X2Y22+] + 2[X2Y4+]

Offline Borek

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Re: Mass Balance: X2Y3
« Reply #1 on: March 22, 2009, 03:02:00 PM »
Where did all the coefficients of 2 and 3 come from??

How many moles of X in a mole of X2Y22+?
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