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Topic: dehydration of alcohol  (Read 8752 times)

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Offline ksr985

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dehydration of alcohol
« on: May 16, 2005, 01:51:21 AM »
Can a hydride or methide shift occur more than once to give more stable cationic intermediates?

for example, if i try dehydrate with H2SO4, the following compound:

PhCH2CH(CH3)CH2CH2OH.

Will the alkene formed be

PhCH=C(CH3)CH2CH3

or

PhCH2C(CH3)=CHCH3

( i think the first is correct )

and will the final intermediate carbocation have the +ve charge on the 3rd or 4th carbon, staring from the right of the chain, ie, from the carbon initially attached to -OH.
i remain, always,
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Offline Mitch

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Re:dehydration of alcohol
« Reply #1 on: May 16, 2005, 02:17:54 AM »
Can a hydride or methide shift occur more than once to give more stable cationic intermediates?


Yes, although calling it "stable" is a misnomer
« Last Edit: May 16, 2005, 02:20:04 AM by Mitch »
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Offline ksr985

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Re:dehydration of alcohol
« Reply #2 on: May 16, 2005, 03:39:52 AM »
but what will be the final intermediate?
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Offline Donaldson Tan

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Re:dehydration of alcohol
« Reply #3 on: May 16, 2005, 09:29:37 PM »
can someone explain the concept of methyl shift?
« Last Edit: May 16, 2005, 09:30:20 PM by geodome »
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Offline movies

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Re:dehydration of alcohol
« Reply #4 on: May 16, 2005, 11:33:06 PM »
can someone explain the concept of methyl shift?

It's like a hydride shift, but with a methyl group.

 ;D

Basically, it's a rearrangement that usually forms a more stable carbocation.  Say you had 3,3-dimethyl-2-butanol and treated it with strong acid to form the secondary carbocation (like the first step of an SN1 reaction).  One of the methyl groups can migrate to quench the secondary carbocation and form a new tertiary carbocation.  Subsequent treatment with a nucleophile like methanol could then capture the carbocation and form a product like 2-methoxy-2,3-dimethylbutane.



This can happen with all kinds of alkyl groups.
« Last Edit: May 16, 2005, 11:33:39 PM by movies »

Offline Donaldson Tan

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Re:dehydration of alcohol
« Reply #5 on: May 17, 2005, 02:45:33 AM »
if i have cyclopentane ring, is it possible for a methyl shift from a ring substituent to enter the ring to form cyclohexane?
"Say you're in a [chemical] plant and there's a snake on the floor. What are you going to do? Call a consultant? Get a meeting together to talk about which color is the snake? Employees should do one thing: walk over there and you step on the friggin� snake." - Jean-Pierre Garnier, CEO of Glaxosmithkline, June 2006

Offline ksr985

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Re:dehydration of alcohol
« Reply #6 on: May 17, 2005, 03:50:34 AM »
i still dont know what the final intermediate in my question is... :(
i remain, always,
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Offline movies

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Re:dehydration of alcohol
« Reply #7 on: May 17, 2005, 12:57:01 PM »
if i have cyclopentane ring, is it possible for a methyl shift from a ring substituent to enter the ring to form cyclohexane?

If you had just methylcyclopentane with a endo-cyclic secondary carbocation, no that wouldn't happen.  You would see a hydride shift to make the tertiary carbocation.

If you had methylcyclopentane and an exo-cyclic primary carbocation then you might see a ring expansion product (forming a secondary carbocation), but more likely you would again see a hydride shift to make the tertiary carbocation.

i still dont know what the final intermediate in my question is... :(

This will depend on whether a tertiary carbocation is more stable than a benzylic carbocation!

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