Well, right off the bat you had a math error. remember, 14.3 mL becomes 0.0143 liters, not .0413 liters.
Now, firstly you have to convert moles of NaOH to moles of CH3COOH, which you did.
That will give you the number of moles of acetic acid in your 10 mL sample. since you took 1/10 of the original, take that number and multiply by 10, then divide by the original volume (10 mL). Here are the calcualtions:
V NaOH x M NaOH = n NaOH
n NaOH = n CH3COOH
n CH3COOH x 10 = original amount of CH3COOH
original # of moles/original volume = conc. CH3COOH in original sample
Remember, since you are doing an acid/base titration, the stuff that is being titrated must be acid, since it is reacting with a base. normal vinegar is a roughly 5% sol'n of acetic acid, along with various other stuff (sugar, water, salt, etc.). You cannot find the conc. of vinegar, since it is not a pure substance.