[mintsharpie]

The evaporation of methanol (molar mass 32.0 g/mol) involves absorption of 1.18 kJ/g. What is the molar enthalpy of vaporization of methanol?

a. 0.0369 kJ/mol
b. 1.18 kJ/mol
c. 3.78 kJ/mol
d. 32.0 kJ/mol
e. 37.8 kJ/mol

Can someone help me solve this? I thought you needed a mass to solve molar enthalpy questions? I'm really confused.

[ARGOS++]

Dear mintsharpie;

You have masses everywhere!
You have mass (gram) per mole, and you have the heat in kJ per mass (gram).
That means that molar weight is also a mass.

So it’s a very simple problem.

Good Luck!
                    ARGOS⁺⁺

[mintsharpie]

Dear mintsharpie;

You have masses everywhere!
You have mass (gram) per mole, and you have the heat in kJ per mass (gram).
That means that molar weight is also a mass.

So it’s a very simple problem.

Good Luck!
                    ARGOS⁺⁺

I still don't understand how to solve the problem. 

[ARGOS++]

Dear mintsharpie;

If you have a heat of 1.18kJ per gram, how much heat you will have for 32.0g (= 1mol)?

Good Luck!
                    ARGOS⁺⁺

[mintsharpie]

Dear mintsharpie;

If you have a heat of 1.18kJ per gram, how much heat you will have for 32.0g (= 1mol)?

Good Luck!
                    ARGOS⁺⁺

Oh! So I'm supposed to go:

1.18 KJ / 1 g
___ KJ / 32.0 g

and multiply 1.18 by 32.0, in order to fill in the blank and arrive at 37.76 kJ/mol?

[ARGOS++]

Dear mintsharpie;

Exact!

Good Luck!
                    ARGOS⁺⁺

[mintsharpie]

Dear mintsharpie;

Exact!

Good Luck!
                    ARGOS⁺⁺

Thanks so much! 

[ARGOS++]

Dear mintsharpie;

You 're welcome!   ─   Soon again.

Good Luck!
                    ARGOS⁺⁺