April 23, 2024, 03:44:40 PM
Forum Rules: Read This Before Posting


Topic: Redox disproportionation?  (Read 4910 times)

0 Members and 1 Guest are viewing this topic.

adamc637

  • Guest
Redox disproportionation?
« on: May 16, 2005, 01:42:46 AM »
What exactly is redox disproportionation?

I had to attend a class advising meeting that coincided with my classes, so I missed this part of the Chemistry lecture! It's not in my book (my professor likes to keep us honest, I guess), and I can't google any good resources... So can anyone point me to a good place to read about it?

Offline ksr985

  • Chemist
  • Regular Member
  • *
  • Posts: 67
  • Mole Snacks: +4/-4
  • Gender: Male
  • typee!
Re:Redox disproportionation?
« Reply #1 on: May 16, 2005, 03:47:41 AM »
a redox disproportionation is a reaction in which the reactant gets oxidized and reduced simultaneously, to yield two products.
example: cannizzarro rxn.

the aldehyde gets oxidized to and acid, and reduced to an alcohol.

A number of inorganic compounds disp when heated. these are generally compounds in which one element is in an intermediate oxidation state, ie, an oxidation state that is neither its highest possible, nor its lowest possible.

example:

Cu2I2--------> Cu + CuI2
i remain, always,
ksr985

Online Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27655
  • Mole Snacks: +1801/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re:Redox disproportionation?
« Reply #2 on: May 18, 2005, 06:42:50 AM »
Cl2 + H2O -> HCl + HClO
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links