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Topic: Balancing An Equation  (Read 3544 times)

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Offline Allowinit

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Balancing An Equation
« on: April 07, 2009, 10:26:05 PM »
We just did a lab today and got the following equation:

Oxalic Acid + Sulphuric Acid + Water + Potassium Permanganate --> Potassium Sulphate + Manganous Sulphate + Water + Carbon Dioxide


H2C2O4 + H2SO4 + H2O + KMnO4 --> K2SO4 + MnSO4 + H2O + CO2

I can't figure out how to balance it, any help?

Offline nj_bartel

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Re: Balancing An Equation
« Reply #1 on: April 07, 2009, 10:48:35 PM »
C
S
Mn
K
O
H

Make a table like that.  On the left hand side, write how many you have of each element in the reactants.  On the right hand side, write how many you have of each element in the products.  Balance from the top down.

Offline Allowinit

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Re: Balancing An Equation
« Reply #2 on: April 07, 2009, 11:07:44 PM »
I tried that out, I just couldn't do it even after that.

I typed it into an auto-balancing thing on the internet just to see how to do it and it said it was invalid.

Offline AWK

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Re: Balancing An Equation
« Reply #3 on: April 08, 2009, 01:00:19 AM »
H2C2O4 + H2SO4 + H2O + KMnO4 --> K2SO4 + MnSO4 + H2O + CO2
Water on the left side is most unnecessary
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Offline Allowinit

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Re: Balancing An Equation
« Reply #4 on: April 08, 2009, 09:31:00 AM »
I woke up this morning and think I figured it out. I think the water was used as somewhat of a 'negative catalyst'. So it's not required on the reactants side.

Offline AWK

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Re: Balancing An Equation
« Reply #5 on: April 09, 2009, 01:14:24 AM »
Water is a result of oxidation.
Read something on Gibbs(free) energy.
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