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Topic: Freezing Point Depression  (Read 3553 times)

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Offline sector9tahiti

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Freezing Point Depression
« on: April 05, 2009, 08:31:28 PM »
A biochemical engineer isolates a bacterial gene fragment and dissolves a 10.5 mg sample of the material in enough water to make 31.3 mL of solution. The osmotic pressure of the solution is 0.340 torr at 25°C.
The molar mass is 18400 g/mol
If the solution density is 0.997 g/mL, how large is the freezing point depression for this solution (Kf of water=1.86°C/m)?

Offline Borek

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Re: Freezing Point Depression
« Reply #1 on: April 06, 2009, 03:16:54 AM »
Show some effort.
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Offline eunChae

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Re: Freezing Point Depression
« Reply #2 on: April 07, 2009, 03:20:27 AM »
osmotic pressure :
   pi = M*R*T (molarity*gas constant* temperature in Kelvin)

freezing point deppression :
  (delta)T = -Kf * m (freezing p.dep. constant * molality)

these would be enough i guess...

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