Hi there, I'm just curious if someone can tell me if I'm doing this correctly. Here's the problem:
Calculate the volume of 2.050 M copper (II) nitrate that must be diluted with water to prepare 750.0 mL of 0.8543 M solution.
So, I used the formula M
1V
1=M
2V
2. Using that formula, I have V
1=(0.8543 M x 750.0 mL)/2.050 M = 312.5 mL. Am I doing this correctly?
Thanks to anyone who can help. Ya'll are saints.