[daylight]

How many mL of NaOH solution required to reach endpoint?

0.497g of propanoic acid is titrated with 0.097 M NaOH. Ka=1.3x10~ How many mL of sodium hydroxide solution would be required to reach endpoint?
Find the pH in the titration at the equivalence point.hmm seems part is missing, but I can fix that if I know how to do it. I don't think my formula is right...

this is what I did, but I think maybe it should be common ion? then ice?
C2H5COOH + NaOH = C2H5COO- + H2O + Na, but maybe the C2H5COO needs to be common ion? I'm not sure either what to do with the propanoic acid in grams since I don't have mL to convert it to molarity. *delete me*?? :-)

endpoint... and equivalence point. Can I just assume 1 Liter to get molarity?

[Borek]

How many mL of sodium hydroxide solution would be required to reach endpoint?

Endpoint? Or equivalence point? In the latter case this a VERY simple simple stoichiometry. Check propanoic acid formula. In the first case - without information about how the endpoint was detected, you won't get far. See

http://www.titrations.info/titration-basic-terms

for both definitions.

Find the pH in the titration at the equivalence point.

This will be pH of a solution of a weak acid salt.

[daylight]

OK I believe it is 1.3x10-5. I wondering if maybe this is a C1V1 problem... hmmm