[applejelly]

You want to cover a motor bike with chromium(3+). You need about 1000g. The ampere is 9.75. How much would you have to pay if it costs 4 cents per KW per hour (KWH)?

I used Q = nF [ n = moles of electrons, F = faraday] to solve for Q. Then, I plugged it in to Q = It to find the time. But after that, I got stuck. How do I find the price?

[Borek]

IMHO question can't be solved with the data given. Could be you are expected to make some assumptions about the required voltage.

[applejelly]

Cr3+ + 3e- --> Cr
The standard reduction potentials at 25 degrees Celsius for this half reaction is -0.73V

Can I assume that is the total voltage? My professor said that it's all the data I need to solve the problem.

[Borek]

It is not all the voltage, but assuming it is you will get lower limit of the cost.

[applejelly]

yeah, i assumed that and got an answer less than 4 cents, which makes no sense..

is there really no way to convert coulombs to kilowatts without voltage?

[Borek]

yeah, i assumed that and got an answer less than 4 cents, which makes no sense.

Why, it can be perfectly right.

is there really no way to convert coulombs to kilowatts without voltage?

No way.