[manjui]

Ok, sorry, the unit is grams. So 2.49*10^-4 grams.

[ARGOS++]

Dear manjui;

Yes!, - You got:  n = 2.49 * 10^-4 of what?   NO! - Its not gram!

Hint: Cancel out all possible units of your equation above.

Good Luck!
                    ARGOS⁺⁺

[manjui]

Ok, I am SO confused. 
The answer of 2.49*10^-4 is not being accepted in my homework as the right answer. It says "Express your answer using two significant figures, m = ____ g"

[ARGOS++]

Dear manjui;

If you do what I told you:

n =  2.6997 L * 1.75 Torr/62.363 L Torr K^1- mol^-1 * 304.15 K = 2.49 * 10^-4

What unit is now left ?

Good Luck!
                    ARGOS⁺⁺

[manjui]

mol^-1

[ARGOS++]

Dear manjui;

A little more correct:  1 / mol^-1  = mol!

Finally:  What is the weight of 1.0 mol Neon?;  -
             - and what is the weight of 2.49 * 10^-4 mol Neon?

Good Luck!
                    ARGOS⁺⁺

[sjb]

Your idea is correct!,  -  But the performance is wrong!     Sorry sjb!

The formula is: A =  r² * pi * l  and not A = d² * pi * l.
And take care for all Units!

Good Luck!
                    ARGOS⁺⁺

My bad, thanks for the catch!

[manjui]

ARGOS++, I have no idea

[ARGOS++]

Dear manjui;

What is the molar mass, also called the molecular weight, of Neon?

Hint: 
Use the periodic table and think about: 1.0 mole Carbon weights 12.011g and 1.0 mole Oxygen weights 16.0g, and 1.0 mole water weights 18.0g.

Good Luck!
                    ARGOS⁺⁺

[manjui]

Got it. Sorry, I was confused with where Neon came in! I got so caught up in the problem that I forgot I was dealing with the amount of Neon in the tube. Thank you for all your help.

[ARGOS++]

Dear manjui;

You 're welcome!   ─   Soon again.

Good Luck!
                    ARGOS⁺⁺