[Ariana]

I was having trouble with a couple of problems (Attached file).

I'm confused about the second Q because I don't understand how 1 equiv of H2 should reduce the unknown reactant. Since KMnO4 attacks a double bond, and H2 reduces a triple bond to double bond, does the original product need a triple bond? When I try to make the molecule, I can't seem to fit in a triple bond in C7H12 =\.

Thanks in advance to any type of help.

[jpg28]

I agree with your answer for Compound B. It is, in fact, methylidenecyclohexane. When terminal alkenes are treated with acidic KMnO₄, it gives of CO₂ as a by-product.

For Compound A, however, seeing as both compounds are just isomers, and the degree of unsaturation for both A and B are 2, the structure you proposed might have deviated from the information given. I suspect compound A to be 3-methylcyclohexene. The first part of question number 2 is somewhat vague, for me, that is, but I just thought of it this way: Compound A reacts with 1 mole equivalent of H₂, and when Compound A (the stock solution) is treated with acidic KMnO₄, the ring opens up and that the unsaturation is the site of cleavage. That's just what I think, though...