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### Topic: Calculate Gibbs energy of Formation , given delta G values ?  (Read 31114 times)

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#### science123

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• Mole Snacks: +1/-2 ##### Calculate Gibbs energy of Formation , given delta G values ?
« on: April 24, 2009, 08:02:32 AM »
Given the following data,

H2(g) + 1/2 O2(g) => H2O(g) DGo = -236.0

2 H(g) + O(g) => H2O(g) DGo = -920.8

2 H(g) + 2 O(g) => H2O2(g) DGo = -1,068.0

2 O(g) => O2(g) DGo = -496.6

H2O2(l) => H2O2(g) DGo = 43.1

Determine DGfo for H2O2(l)

Correct : -178.0

I don't know which equations to combine and flip and how do we find the Gf of H2O2 (gas) . I was thinking of someway to find gf of H2O2 gas and subract from Grxn to get Gf of H2O2 liquid. Thanks!

#### sjb

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« Reply #1 on: April 24, 2009, 08:06:23 AM »
What's the definition of  :delta: Gf?

#### science123

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• Mole Snacks: +1/-2 ##### Re: Calculate Gibbs energy of Formation , given delta G values ?
« Reply #2 on: April 24, 2009, 08:10:05 AM »
What's the definition of  :delta: Gf?

Change of Gibbs free energy that accompanies the formation of 1 mole of that substance from it's elements in standard state.

#### sjb

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« Reply #3 on: April 24, 2009, 08:12:06 AM »
What's the definition of  :delta: Gf?

Change of Gibbs free energy that accompanies the formation of 1 mole of that substance from it's elements in standard state.

Right, so what does that mean, in terms of your reaction?

#### science123

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• Mole Snacks: +1/-2 ##### Re: Calculate Gibbs energy of Formation , given delta G values ?
« Reply #4 on: April 24, 2009, 08:20:49 AM »
Delta Go = sum of Delta Gf of products - sum of Delta Gf of reactants
Am i right?

#### sjb

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« Reply #5 on: April 24, 2009, 08:26:21 AM »
Essentially, yes. You're after  :delta: Gf for H2O2(l), which is for the reaction H2(g) + O2(g) H2O2(l). Can you find a path using the data you have that allows you to calculate this  H2(g) + O2(g)   C ... H2O2(l)?

#### science123

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• Mole Snacks: +1/-2 ##### Re: Calculate Gibbs energy of Formation , given delta G values ?
« Reply #6 on: April 24, 2009, 08:40:52 AM »
That's that part i am not getting. And btw why does eq. 2 has hydrogen in atomic form?

#### sjb

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« Reply #7 on: April 24, 2009, 08:54:02 AM »
You won't necessarily have to use them all (I've not worked it through, so could be wrong here).

For instance, from

H2(g) + 1/2 O2(g) H2O(g)  :delta: Go = -236.0

2 H(g) + O(g) H2O(g)  :delta: Go = -920.8

H2(g) + 1/2 O2(g) H2O(g) 2 H(g) + O(g)

you can calculate  :delta: Gf for 2 H(g) + O(g), by adding equation 1 to the reverse of equation 2; giving 684.8. (Don't forget your units!)