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Dear mr cool;What is the mass of water of the calorimeter?? It is required!For 2.: Use: q = m * c * ∆T For c_{water} see on: http://www.engineeringtoolbox.com/water-thermal-properties-d_162.html For 3.: Use: q = c * m * ∆T and: Q_{gain} = Q_{loss}.(Search the forums; there are several similar/identical questions.)Good Luck! ARGOS^{++}

Dear mr cool;No! – The unit is only Joule! Do the calculation with all units and cancel them out!Good Luck! ARGOS^{++}

From the link I gave you: c_{Water}(l) = 4.187 J °K^{-1} g^{-1}

Dear mr cool;For 3.) you have to solve the formula q = c * m * ∆T for c_{metal} and use the correct values for mass and ∆T. Good Luck! ARGOS^{++}

For 3.) you have to solve the formula q = c * m * ∆T for c_{metal} and use the correct values for mass and ∆T.