I know this question is basic, but I am not sure my anwswer is right or not.
I was given a 37% w/w HCl which I have to dilute it to a 50 ml of 2 Mol/L HCl.
The way i am doing it is:
Mass of HCl present in the target solution, 50 ml of 2 Mol/L = ( 2 x 36.5) / (1000 / 50) = 3.65 g
As every 100g of the Concentrated acid contains 37g of HCl,
The amount need for dilution = (3.65 / 37) x 100 = 9.86g
i.e. Weight 9.86g of the conc. HCl and add water to 50 ml to get the target solution.
Is the above calculation correct or not?