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Topic: Finding mmoles added in a solution  (Read 4215 times)

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Offline ItalianChick0188

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Finding mmoles added in a solution
« on: May 07, 2009, 12:16:29 PM »
If I titrated 0.0100 M Ce4+ with an unknown substance containing Fe2+ that weighs 0.0249 grams and my equilibrium point is 1.38 mL; How can I find the mmoles of Ce4+ added at the equilibrium point?

Fe2+ + Ce4+ -----> Fe3+ + Ce3+

So far I have 1.50 mL X 0.00001 mmol = 0.000015 mmoles Ce4+ added at equilibrium?
« Last Edit: May 07, 2009, 12:37:22 PM by ItalianChick0188 »

Offline Borek

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Re: Finding mmoles added in a solution
« Reply #1 on: May 07, 2009, 12:45:10 PM »
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info, pH-meter.info

Offline ItalianChick0188

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Offline ItalianChick0188

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Re: Finding mmoles added in a solution
« Reply #3 on: May 07, 2009, 02:34:38 PM »
I figured it out.

the 0.00015 is the moles of Ce4+ and then converting to mmoles it would be 0.15 mmoles.

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