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.0320 M hydrochloric acid
.320 M HCl
0.00674 mol CaCO3
0.00647 mol CaCO3
42.15 mL sol'n x .320 M HCl/1000 mL sol'n x 1 mol CaCO3/2 mol HCl = 0.00674 mol CaCO3
Quote42.15 mL sol'n x .320 M HCl/1000 mL sol'n x 1 mol CaCO3/2 mol HCl = 0.00674 mol CaCO3Where you taken into account that CaCO3 reacts with 2 moles of HCl?
675 mg of calcium carbonate
QuoteYes he did P.S. you assume I'm a he
Yes he did
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