0 Members and 1 Guest are viewing this topic.
.0320 M hydrochloric acid
.320 M HCl
0.00674 mol CaCO3
0.00647 mol CaCO3
42.15 mL sol'n x .320 M HCl/1000 mL sol'n x 1 mol CaCO3/2 mol HCl = 0.00674 mol CaCO3
Quote42.15 mL sol'n x .320 M HCl/1000 mL sol'n x 1 mol CaCO3/2 mol HCl = 0.00674 mol CaCO3Where you taken into account that CaCO3 reacts with 2 moles of HCl?
675 mg of calcium carbonate
QuoteYes he did P.S. you assume I'm a he
Yes he did
Page created in 0.042 seconds with 21 queries.