March 28, 2024, 08:13:56 AM
Forum Rules: Read This Before Posting


Topic: Finding mmoles added in a solution  (Read 4414 times)

0 Members and 1 Guest are viewing this topic.

Offline ItalianChick0188

  • Regular Member
  • ***
  • Posts: 21
  • Mole Snacks: +0/-0
Finding mmoles added in a solution
« on: May 07, 2009, 12:16:29 PM »
If I titrated 0.0100 M Ce4+ with an unknown substance containing Fe2+ that weighs 0.0249 grams and my equilibrium point is 1.38 mL; How can I find the mmoles of Ce4+ added at the equilibrium point?

Fe2+ + Ce4+ -----> Fe3+ + Ce3+

So far I have 1.50 mL X 0.00001 mmol = 0.000015 mmoles Ce4+ added at equilibrium?
« Last Edit: May 07, 2009, 12:37:22 PM by ItalianChick0188 »

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27637
  • Mole Snacks: +1799/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Finding mmoles added in a solution
« Reply #1 on: May 07, 2009, 12:45:10 PM »
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline ItalianChick0188

  • Regular Member
  • ***
  • Posts: 21
  • Mole Snacks: +0/-0

Offline ItalianChick0188

  • Regular Member
  • ***
  • Posts: 21
  • Mole Snacks: +0/-0
Re: Finding mmoles added in a solution
« Reply #3 on: May 07, 2009, 02:34:38 PM »
I figured it out.

the 0.00015 is the moles of Ce4+ and then converting to mmoles it would be 0.15 mmoles.

Sponsored Links