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Topic: Gummy Bear Sacrafice  (Read 3610 times)

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Offline Newbie03

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Gummy Bear Sacrafice
« on: May 11, 2009, 08:38:19 PM »
I've seen the gummy bear sacrifice demo classified as a redox reaction however, I'm having trouble with this.
When heated, potassium chlorate decomposes as:
2KClO3 --> 2KCl + 3O2
products would be:
K: +1
Cl: -1
O2: 0
reactants though:
O: -2 but since there is 3 O's that's a -6 so I'm not sure how KCl makes a +6 charge.

After this, we have:
C12H22O11 + O2 --> 9C + 3CO2 + H2O
reactants:
C: 0
H: +1
O (of sugar): -2
O (diatomic): 0
products:
C (elemental): 0
C (carbon dioxide): +4
O: -2
H: +1

Where is the redox? What am I missing??

Offline Lone Proton

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Re: Gummy Bear Sacrafice
« Reply #1 on: May 12, 2009, 12:43:54 AM »
The KCL doesn't make a +6 charge, the Cl makes a +5 charge, because its a "variable atom" says my chem teacher. Other variable atoms you should take in mind are C, S, N, and more...

Offline c0d3

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Re: Gummy Bear Sacrafice
« Reply #2 on: May 12, 2009, 09:34:11 PM »
The KCL doesn't make a +6 charge, the Cl makes a +5 charge, because its a "variable atom" says my chem teacher. Other variable atoms you should take in mind are C, S, N, and more...

It's true that Cl in potassium chlorate has a oxidation state of +5. Cl will be reduced from +5 to -1 and O is oxidizes from -2 to 0

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