[laxgirl]

I don't understand this problem...need *delete me*

Sulfuric acid ionizes in two steps in water solution. for the first ionization shown in the following reaction Ka is so large that in moderately dilute solution the ionization can be considered 100%
H2S04 H30+ +Hs04-
The second ionization is fairly strong, and Ka = 1.3X10-2
HSO4- + H2O  ::equil::H30+ +SO-2 4
Calculate the total [H30+] and PH of a 0.0788M H2SO4 solution. 

the only help my teacher gave me is that if the 1st ionization is 100% what will [HSO4] be and to account for the already existing concentration of H30+ in the 2nd ionization. & to let X=[SO4 2-]

[Borek]

http://www.chembuddy.com/?left=pH-calculation&right=pH-polyprotic-acid-base

http://www.chembuddy.com/?left=pH-calculation&right=pH-polyprotic-simplified