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Topic: cyclohexanone flipping and elimination (?)  (Read 3478 times)

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Offline g_orbital

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cyclohexanone flipping and elimination (?)
« on: May 18, 2009, 04:26:07 PM »

In principle, could cyclohexanone (either substituted or not) flip from one chair conformation to the other, like cyclohexane?
Particularly, suppose one position in the cyclohexanone is substituted by a good leaving group (say halide), in the equatorial position. From the geometric point of view, an elimination couldn't occur, because the leaving group is not antiperiplanar to the hydrogen. However, if theoretically the cyclohexanone ring could be inversed, the substituent becomes axial, making the elimination event now geometrically feasible.
What do you think?

Thanks in advance.

Offline spirochete

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Re: cyclohexanone flipping and elimination (?)
« Reply #1 on: May 19, 2009, 07:58:24 PM »
Yes the same geometrical constraints that apply to reactions of cyclohexane also apply to cyclohexanone. 

Offline nj_bartel

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Re: cyclohexanone flipping and elimination (?)
« Reply #2 on: May 19, 2009, 08:05:29 PM »
How does flipping about that carbon work with retention of the pi bond?

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