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Topic: Lab-Acid-Base Titration-Question about finding Moles KOH  (Read 4062 times)

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Offline Solid8Snake

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Lab-Acid-Base Titration-Question about finding Moles KOH
« on: May 20, 2009, 11:29:57 PM »
Purpose to determine the concentration of an unknown potassium hydroxide, KOH solution using a colormetric

tip: Calculate the concentration of KOH assuming a monoprotic acid.   (1:1 ratio)

So basically I have the Mass of the acid which is 0.3g
I found the moles of acid which is 1.469004015x10^-3
But how do you find the moles of KOH?

additional information:
Potassium biphthalate (acid): 204.22 g/mol
potassium hydroxide, KOH (base): 56.097 g/mol

Any help would be greatly appreciated

Offline sjb

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Re: Lab-Acid-Base Titration-Question about finding Moles KOH
« Reply #1 on: May 21, 2009, 02:10:56 AM »
Purpose to determine the concentration of an unknown potassium hydroxide, KOH solution using a colormetric

tip: Calculate the concentration of KOH assuming a monoprotic acid.   (1:1 ratio)

So basically I have the Mass of the acid which is 0.3g
I found the moles of acid which is 1.469004015x10^-3
But how do you find the moles of KOH?

additional information:
Potassium biphthalate (acid): 204.22 g/mol
potassium hydroxide, KOH (base): 56.097 g/mol

Any help would be greatly appreciated

Well, if you have 1.4 x 10-3 mol of acid, and acid reacts in a 1:1 ratio with KOH.. ?

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