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### Topic: SOLUBILITY!!  (Read 20470 times)

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#### Borek

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##### Re: SOLUBILITY!!
« Reply #15 on: June 17, 2009, 04:33:29 AM »
so,in the end the Ksp of salt XY is higher than Ksp for salt X2Y3 then i can know that salt XY is more soluble than salt X2Y3.

If by "i can know that salt XY is more soluble than salt X2Y3" you mean "I will get to the wrong conclusion that salt XY is more soluble than salt X2Y3" - you are right.
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#### killer120

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##### Re: SOLUBILITY!!
« Reply #16 on: June 17, 2009, 08:03:30 AM »
so,in the end the Ksp of salt XY is higher than Ksp for salt X2Y3 then i can know that salt XY is more soluble than salt X2Y3.

If by "i can know that salt XY is more soluble than salt X2Y3" you mean "I will get to the wrong conclusion that salt XY is more soluble than salt X2Y3" - you are right.
maybe my English is too weak.....i can't get what you trying to tell me...about the question you give....am i giving the correct answer?

#### killer120

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##### Re: SOLUBILITY!!
« Reply #17 on: June 18, 2009, 10:44:11 AM »
Rank the following five salts in order of decreasing solubility, in terms of mass per unit volume.
(The most soluble gets rank 1, the least soluble gets rank 5.)

Ag3PO4     (Ksp = 1.80×10-18)
Ag2CrO4     (Ksp = 9.00×10-12)
Ca5(PO4)3F     (Ksp = 1.00×10-60)
Ca3(PO4)2     (Ksp = 1.30×10-32)
AgCl     (Ksp = 1.60×10-10)

So here is my work:

i first found the concentration of the ions:
Ag3PO4 : 1.60685E-5 M
Ag2CrO4 : 1.31037E-4 M
Ca5(PO4)3F : 6.109086E-8 M
Ca3(PO4)2 : 1.644765E-7 M
AgCl : 1.264911E-5 M

Then i used the concentrations and multiplied it by the molar mass and got the following solubilities [g / L]
Ag3PO4 : .0067259 g/L
Ag2CrO4 : .0434687 g/L
Ca5(PO4)3F : 3.0808E-5 g/L
Ca3(PO4)2 : 5.10167E-5 g/L
AgCl : .0081288 g/L

So the salt with the highest solubility would be the salt with the highest number:
3) Ag3PO4
1) Ag2CrO4
5) Ca5(PO4)3F
4) Ca3(PO4)2
2) AgCl

The rank that i have shown is incorrect
and i dont know why
can someone PLEASE check my work
THANK YOU!!