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Topic: Enthalpy of vaporization  (Read 3640 times)

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Offline Shaun1979

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Enthalpy of vaporization
« on: June 17, 2009, 10:15:39 AM »
Hi,

I have the following question to answer….

The enthalpy change for the vaporization of methanol, CH3OH, at 25 degrees celcius is 37.43 kj/ mol. What quantity of heat energy must be used to vaporize 25.0g of methanol at 25 degrees celcius?

Am I meant to use the Clausius – Clapeyron equation to solve it? I am so confused because in out notes we are told not to study this equation, as it’s not part our current study module, but it’s the only equation that I can think to use?

Can anyone help?


Offline Astrokel

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Re: Enthalpy of vaporization
« Reply #1 on: June 17, 2009, 10:32:48 AM »
 :delta: Hvap = Q/n
No matters what results are waiting for us, it's nothing but the DESTINY!!!!!!!!!!!!

Offline Shaun1979

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Re: Enthalpy of vaporization
« Reply #2 on: June 18, 2009, 09:18:24 AM »
Oh right...thanks....was digging a bit too deep!

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