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Topic: Balancing Equations and doing net ionic eqyations?  (Read 2470 times)

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Offline Student09

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Balancing Equations and doing net ionic eqyations?
« on: June 06, 2009, 11:12:46 PM »
I have my Chemistry final on Monday and my biggest problem is I have trouble balancing equations and doing net ionic equations. If anybody could break it down in simple steps and examples I would really appreciate it....

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Offline Fridushka

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Re: Balancing Equations and doing net ionic eqyations?
« Reply #1 on: June 07, 2009, 05:39:49 AM »
well I'm not that sure, because i just checked my high school copybook and found an example including ionic and net ionic equations, it has been long time haven't reviewed it,
so, I have an example of a redox reaction:
Oxidation 1/2 rxn: Mg(s)  :rarrow: Mg2+ + 2 e-
Reduction 1/2 rxn: 2H+ + 2 e- :rarrow: H2(g)
Overall rxn: Mg(s) + 2H+  :rarrow: Mg2+ + H2(g)
Chemical eqn:  Mg(s) + 2 HCl  :rarrow: MgCl2(aq) + H2(g)
Ionic eqn: Mg(s) + 2H+ + 2 Cl-  :rarrow: Mg2+ + 2Cl- + H2(g)
Net-ionic eqn: Mg(s) + 2H+  :rarrow: Mg 2+ + H2(g)

well its seems that the difference between the ionic and the net ionic equations is the abscence of the spectator ion, the Cl-. Moreover, in the ionic equation include all the ion involved, and the net ionic just the ones in the half reaction.

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