I am really bad at chemistry. My main problem is figuring out how to set up a problem. Could anyone help me with this problem?
Stomach acid, a dilute solution of HCl in water, can be neutralized by reaction with sodium bicarbonate, NaHCO3, according to the equation:
HCl(aq) + NaHCO3 ----> NaCl(aq) + H2O(l) + CO2
How many mL of 0.125 M NaHCO3 solution are needed to neutralize 18.0 mL of 0.100 M HCL?