[KranLU1024]

I am really bad at chemistry. My main problem is figuring out how to set up a problem. Could anyone help me with this problem?

Stomach acid, a dilute solution of HCl in water, can be neutralized by reaction with sodium bicarbonate, NaHCO3, according to the equation:

HCl(aq) + NaHCO3 ----> NaCl(aq) + H2O(l) + CO2

How many mL of 0.125 M NaHCO3 solution are needed to neutralize 18.0 mL of 0.100 M HCL?

[Garneck]

C₁V₁=C₂V₂

[xiankai]

that formula applies when 1 mol of x and reacts with 1 mol of y, and both x and y are in the same state i suppose.

on a side note, HCl and NaHCO3 react first to produce NaCl and HCO3 first, at which the carbonic instantly dissociates to form H2O and CO2.

[KranLU1024]

Thanks so much! I really appreciate it! So all I have to do is just plug those numbers into the C1V1=C2V2 formula since we are assuming that they equal 1 mol?

[Garneck]

that formula applies when 1 mol of x and reacts with 1 mol of y, and both x and y are in the same state i suppose.

That's why I wrote it.

[KranLU1024]

Thanks so much! I was just confused.

[arnyk]

Be careful when the molar ratios aren't perfectly 1:1 in which case you would have to adjust the equation accordingly.  

2 NaOH + H2CO3 --> Na2CO3 + 2 H2O

2c1V1 = c2V2