April 20, 2024, 03:18:22 AM
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Topic: What mass of lead II oxide is obtained by heating 33.1g of lead II nitrate-CHECK  (Read 4927 times)

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Offline busi6292

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I think I have got this sorted. Please check this one. The question is in the title. The formula and working out I got is:

            2Pb(NO3)2        ---->    2PbO      +     4NO2     +    O2

RAM     NO3 = 62 X 2                  207 + 16 = 223           
          124 + 207 = 331               X 2 moles
          331 X 2moles = 662            = 446

662/662                                        446/662

446/662 X 33.1g = 22.3g as the answer?

Please tell me I am right! Thanks


Offline plankk

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You're right.  ;)

Offline busi6292

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Wow im a genius!

(cant wait to give it up)

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