[positiveion]

I was attempting to do this work sheet and got stuck on 1 b.
http://www.scribd.com/doc/9575774/Limiting-Reagent-Worksheet

This is what I managed to do, can you tell how to continue?

NH4NO3:
80.06 amu
80.06 g/mol

30/80.06 = 0.37
Therefore I have 0.37 moles of ammonium nitrate


Na3PO4:
163.94 amu
163.94 g/mol

50/163.94 = 0.30
Therefore I have 0.30 moles of Sodium Phosphate

a) As the ratio of ammonium nitrate to sodium phosphate is 3:1 and 0.37 is not 3 times more than 0.30, then ammonium nitrate is the limiting reagent

b) i don't know how to do b.

[Borek]

You just calulate amounts assuming limiting reagent reacted to the end.

[positiveion]

um

i do not understand that

[Borek]

But you know how to do basic stoichiometry?

Forget everything else - just calculate how much products you will get starting with 30 grams of ammonium nitrate.

[positiveion]

I don't know how to do the ratios though and thats the only way I know how to follow up this kind of problem.

Like when I did the problem with an easier one I modified it from

4NH3 + 5O2 --> 4NO + 6H2O

to

.8NH3 + 1O2 --> .8NO + 1.2H2O

and then multiplied it

I don't know how to do this for this problem.

[Borek]

You should not touch the coefficients - they are what they are and they should be not changed.

http://www.chembuddy.com/?left=balancing-stoichiometry&right=stoichiometric-calculations