Ahh... I actually got this assigned to me today too... Can someone help me?
THis is what i did so far:
i made two half reactions:
MnO4- ---> MnS and S2- ---> S
Then i balanced the charges and elements on both and i got:
4H+ + S + MnO4- + 3e- ---> MnS + 4H2O
S2- ---> S + 2 e-
then i balanced the electrons on both the equations so they would cancel out:
2(4H+ + S + MnO4- + 3e- ---> MnS + 4H2O)
3(S2- ---> S + 2 e-)
THEN I put the equations together and got:
8H+ + S + 2MnO4- + 3S2- ---> 2MnS + 8H2O + 3S
I'm not sure if i did that last step right...
but after that since there's 8H on the right I added 8OH- to both sides... is that correct?
so the final equation i got was
8OH- + 8H+ + S + 2MnO4- + 3S2- ---> 2MnS + 8H2O + 3S + 8OH-
Did I do any of this right!?
If I'm doing anything wrong... What is it?