we have this lab for Ka of ethanoic acid (vinegar) and im really confused about the reaction and ICE table
we did titration NaOH with ethanoic acid and found the pH graph using CBL units
then the teacher gave us this reaction to use in ICE table:
CH3COOH > H + CH3COO
but y isnt it CH3COOH + NaOH > watever comes here
anyways, when i make ICE, i calculated the initial moles of ethanoic acid, and for H and CH3COO they'll be 0 (thats wat the teacher said).
1-but i dont know how to calculate the change of moles for all of them.
2-i also dont know what this step (4b) says: Using the initial pH recorded, calculate the hydronium ion concentration of
the ethanoic acid solution. (whcih pH shoud i use?)
this is what i got so far
CH3COOH H CH3COO
I .98 0 0
for a link of the lab procedure.. here it is:http://www.stemnet.nf.ca/courses/chem3202/unit02_org03_ilo07/c3_lab_04.pdf
and the step 4B, i odnt get it
help me please