March 29, 2024, 01:48:56 AM
Forum Rules: Read This Before Posting


Topic: equilibrium constant  (Read 5515 times)

0 Members and 1 Guest are viewing this topic.

Ice-cream

  • Guest
equilibrium constant
« on: June 15, 2005, 09:33:48 AM »
for equilibrium constants, when K<1, the reactants are favoured, when K>1 the products are favoured and when K=1...what happens?

angelguy

  • Guest
Re:equilibrium constant
« Reply #1 on: June 15, 2005, 09:40:42 AM »
It means that the gibbs energy change between the reactant and the product is zero. Which is why k =1 as in del G = -RTlnK.

Thanks,
angelguy



Offline Juan R.

  • Chemist
  • Full Member
  • *
  • Posts: 148
  • Mole Snacks: +24/-3
  • Gender: Male
    • The Center for CANONICAL |SCIENCE)
Re:equilibrium constant
« Reply #2 on: June 16, 2005, 04:02:47 AM »
For

A <--> B

in the concentration approx.

K = CB/CA

for K = 1, CB = CA. There is not preference between reactants and products. Both are equally "stable".

An "trivial" example is ammonia inversion

          H \
A =    H - N:
          H /

            / H
B =    :N - H
            \ H

« Last Edit: June 16, 2005, 04:08:22 AM by Juan R. »
The first canonical scientist.

Sponsored Links