[Kipper]

For the following reaction, 0.155 moles of barium chloride are mixed with 0.373 moles of potassium sulfate.

barium chloride (aq) + potassium sulfate (aq)  = barium sulfate (aq) + potassium chloride (aq)

(A) What is the formula for the limiting reagent? (I'll be honest I'm not quite sure what they mean by this)

(B) What is the maximum amount of Barium Sulfate that can be produced.

Ok so the first thing I did is set up a balanced equation (hopefully I did this accurately):

2BaCl2 + 2K2(SO4) ------> Ba2(SO4)2 + 4KCl

Then I did the following to try and determine the limiting agent:

0.155 mol (BaCl) x 1 mol (BaSO4) / 2 mol BaCl = 0.0775 mol of BaSO4

0.373 mol (KSO4) x 1 mol (BaSO4) / 2 mol KSO4 = 0.1865 mol of BaSO4

Therefore I believe the limiting reagent is BaCl because it produces only 0.0775 mol.

Does this seem right?

Also, does anyone have an idea as to what the 'Formula of the limiting reagent could be'?

Thank you in advance. 

[UG]

Your equation is wrong, unfortunately. Barium is in group 2, so it forms a 2+ ion like calcium and magnesium. The formulae for barium sulfate is wrong. You had it correct when you did 

0.155 mol (BaCl) x 1 mol (BaSO4) / 2 mol BaCl = 0.0775 mol of BaSO4

0.373 mol (KSO4) x 1 mol (BaSO4) / 2 mol KSO4 = 0.1865 mol of BaSO4