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Topic: Net Ionic Equation  (Read 2257 times)

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Offline molemole

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Net Ionic Equation
« on: October 19, 2009, 11:11:21 PM »
I have a 0.060 M acetic acid solution. The pH at the equivilance point after titration with 0.100 M NaOH is 8.50. How would I write a net ionic equation that accounts for the formation of the excess OH ions? Thanks.

Offline AWK

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Re: Net Ionic Equation
« Reply #1 on: October 20, 2009, 02:05:24 AM »
Hydrolysis (protolysis) of acetate ion.
AWK

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