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### Topic: Need to check if correct  (Read 2530 times)

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#### stoicheomexic

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• Mole Snacks: +0/-0 ##### Need to check if correct
« on: October 29, 2009, 02:01:11 PM »
Just made this account , because i want to be sure if i solved this exercices correct
Would really appreciate it if somebody could just point me in the right direction if i got any wrong
N2 + 3 H2 = 2 NH3
N2 = 125 grams 4.5 moles
H2 = 32 grams 48 moles
NH3 = 36.5 grams 4.2 moles
Rendement (=output according online translator)(NH3) = 51% >>correct??

2 C6H6 + 15 O2 = 12 CO2+ 6 H2O
C6H6 = 10 grams
H2O = 6.9 grams >> correct??
Volume CO2 = 103 liters >>correct??

C2H6 = C2H4 + H2
C2H4 = 30 liters
rendement (C2H4) = 67% >> correct?

#### Dan ##### Re: Need to check if correct
« Reply #1 on: October 30, 2009, 07:38:31 AM »
N2 + 3 H2 = 2 NH3
N2 = 125 grams 4.5 moles
H2 = 32 grams 48 moles
NH3 = 36.5 grams 4.2 moles
Rendement (=output according online translator)(NH3) = 51% >>correct??

The highlighted mole calculations seem to have gone wrong, and consequently your yield (rendement = yield) is wrong.

Quote
2 C6H6 + 15 O2 = 12 CO2+ 6 H2O
C6H6 = 10 grams
H2O = 6.9 grams >> correct??
Volume CO2 = 103 liters >>correct??

I agree with your mass of water, but not with your volume of CO2, can you show working?

Quote
C2H6 = C2H4 + H2
C2H4 = 30 liters
rendement (C2H4) = 67% >> correct?

This calculation is impossible without knowing how much ethane you started with...
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