Actually 1 more question please. 5g Ca added to HCl
using the weight of the metal used and moles of H2gas produced calculate the atomic weight of the metal.
so for Ca
n=V/Vm, n(h2)=0.232L/24.1Lmol so 0.010 mol (H2)
M=n/m ,M(Ca)=0.010mol/0.5g=0.02gmol? {M=atomic weight}
0.02gmol could not be the atomic weight of calcium in this reaction could it?