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Topic: Need help with a little titration?  (Read 2426 times)

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Offline pewpew

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Need help with a little titration?
« on: January 02, 2010, 09:18:09 PM »
Alright, so I did a lab titrating saturated Ca(OH)2 with HCl (0.100M), and have these results:
Amount HCl added (mol): 1.081 x 10^-3
Amount OH in saturated Ca(OH)2 (mol): 1.614x10^-4 (given volume of saturated Ca(OH)2 was 25ml)

So, what i now need to find is [OH-] at equilibrium and [Ca2+] at equilibrium, which I have no clue.

Oh, please don't say use Ksp value of calcium hydroxide, cause that's what I'm supposed to find out once i get [oh-] and [Ca2+]

If needed, temperature was 20.9 degrees celcius, which I have no clue what part it plays in.
Also, can ayone tell me what the mol per liter is for a "saturated" calcium hydroxide?

Offline Borek

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Re: Need help with a little titration?
« Reply #1 on: January 03, 2010, 04:10:18 AM »
Can you write equation of Ca(OH)2 dissolution?

According to this equation, what should be concentration of Ca2+ if concentration of OH- is 1.614x10-4?
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Offline pewpew

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Re: Need help with a little titration?
« Reply #2 on: January 04, 2010, 09:23:48 PM »
So for every 2 (OH) mol there is 1 mol of Ca, so 8.07 x 10^-5.

Thanks so much.

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