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Topic: Simplest formula for original compound  (Read 3969 times)

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peggysue32

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Simplest formula for original compound
« on: July 05, 2005, 12:08:06 PM »
Hi, I'm new here, and Im currently in grade 12 chem.  I dont have a teacher, because im doing this course at home and it would be great if any of you could help.

"A compound containingn titanium and chlorine is analyzed by converting all the titanium into 1.20g of TiO2 and all the chlorine into 6.45g of AgCl.  What is the simplest formula for the original compound?"

Thanks,
peggysue32

arnyk

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Re:Simplest formula for original compound
« Reply #1 on: July 05, 2005, 12:32:56 PM »
They are asking for the empirical formula.

Find the moles of Cl and the moles of Ti given those masses.

Knowing the moles, use the ratio to determine the empirical formula.

Here's a simple example:

In a compound...

You have 32.32g of H.  

You have 96.08g of C.

What is the empirical formula?

32.32g of H = 32 mol
96.08g of C = 8 mol

So the ratio C : H is 8 mol : 32 mol which simpifies to 1: 4.

1C : 4H

The empirical formula is CH4.

You may have covered this in grade 11 chemistry.
« Last Edit: July 05, 2005, 12:39:04 PM by arnyk »

Offline Donaldson Tan

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Re:Simplest formula for original compound
« Reply #2 on: July 07, 2005, 02:16:51 PM »
the gist is to find the molar ratio of each element.
"Say you're in a [chemical] plant and there's a snake on the floor. What are you going to do? Call a consultant? Get a meeting together to talk about which color is the snake? Employees should do one thing: walk over there and you step on the friggin� snake." - Jean-Pierre Garnier, CEO of Glaxosmithkline, June 2006

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