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Topic: Heat of Reaction per Mole  (Read 8030 times)

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Offline Glorzifen

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Heat of Reaction per Mole
« on: December 06, 2009, 02:34:04 PM »
100.0ml of 0.500M HCl at 20.5C is reacted with 3.27g of Zn. The solution warms to 26.2C. What is the heat of reaction per mole of Zn?

I've gotten the mass of HCl = 1.8g (using n = C/V and n = m/M) and figure that I've got to use q=mcΔT but I'm confused as to where to go from here. What is the next step?

Thanks

Offline Glorzifen

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Re: Heat of Reaction per Mole
« Reply #1 on: December 07, 2009, 06:09:17 PM »
Okay...

So since the heat of the zinc is transferred to the HCl (-qzinc=qHCl), I can express the relationship as: -mcΔT = mcΔT...which, when filled in looks like:

-(3.27g)(388)ΔT = 1.82g(4.18)(5.7) (I had to google Zn's specific heat capacity)
ΔT = -34
Tizinc = 60.2

Then go back to q=mcΔT to find the q for zinc? The correct answer is -4.8kJ/mol apparently but I'm not sure if I'm even going in the right direction.

Offline Glorzifen

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Re: Heat of Reaction per Mole
« Reply #2 on: December 07, 2009, 07:35:04 PM »
Got it figured out, if anyone's interested. Just forgot some of the basics.

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