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Topic: H NMR n+1 rule question  (Read 4097 times)

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Offline science123

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H NMR n+1 rule question
« on: December 07, 2009, 11:43:34 PM »
I tried predicting the structure and checked using the n+1 rule. All the H comply with the rule except for the H on the middle carbon . It is supposed to give 24 lines [ (n+1)*(n+1)*(n+1) --> (2+1)(3+1)(1+1) = 24 lines] since all the neighboring protons are non-equivalent to each other. Any suggestions?

http://img13.imageshack.us/img13/6717/nmry.jpg

Offline opuktun

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Re: H NMR n+1 rule question
« Reply #1 on: December 09, 2009, 06:05:19 AM »
The middle atom has five neighbours...

So the (5+1)=6 peaks is correct.

What's with the 24?

If the scanning resolution of NMR is not sensitive enough, you would not see further splitting.

Offline science123

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Re: H NMR n+1 rule question
« Reply #2 on: December 10, 2009, 09:41:36 PM »
The middle atom has five neighbours...

So the (5+1)=6 peaks is correct.

What's with the 24?

If the scanning resolution of NMR is not sensitive enough, you would not see further splitting.

It's not 24 my bad! You are right that the resolution of NMR is not sensitive enough so i could see the max theoritical peaks but my prof. told me that only non-equivalent protons split and the protons counting towards N should be equal to each other to apply N+1 rule but if they aren't like in this problem (ch2 and ch3 ) then (n+1)(n+1) rule applies.

(2+1)(3+1) = 12 peaks theoretically.

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