I have been given this question in a sample set of questions. I was wondering if anyone could help in getting the solution. I will tell you the answer:
Ni2+ = 0.0124M and Zn2+ = 0.00718
The question is:
"A 50.0-mL solution containing Ni2+ and Zn2+ was treated with 25.0-mL of 0.0452M EDTA to bind all the metal. The excess unreacted EDTA required 12.4-mL of 0.0123M Mg2+ for complete reaction. An excess of reagent 2,3-dimercapto-1-propanol was then add to displace the EDTA from zinc. Another 29.2-mL of Mg2+ were required to for reaction with the liberated EDTA. Calculate the molarity of Ni2+ and Zn2+ in the original solution.
If anyone can help that would be great seeing as i can't even get the proper mols of EDTA needed.