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Topic: A mixture of Nitroglycerin and Ammonium Nitrate produces?  (Read 6260 times)

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Offline rzbizzy

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A mixture of Nitroglycerin and Ammonium Nitrate produces?
« on: December 15, 2009, 01:56:10 AM »
A mixture of one mole of Nitroglycerin and one mole of Ammonium Nitrate produces? I need to find out the detonation equation for this and calculate the energy released (kJ/kg) by this reaction. Thanks.

Offline rzbizzy

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Re: A mixture of Nitroglycerin and Ammonium Nitrate produces?
« Reply #1 on: December 15, 2009, 02:01:41 AM »
nitroglycerin – C3H5N3O9         Ammonium Nitrate – NH4NO3

I'm not sure how what product you get, and the name of the product.
So far, if I just add the two together, i get
(C3H9N5O12) → N2 + H20 + CO2 + O2
5N → 2.5N2
9H + 4.5O→ 4.5H2O (7.5 O remains)
3C + 3O → 3CO  (9 O remains)
9O → 4.5O2

(C3H9N5O12) → 2.5N2 + 4.5H20 + 3CO + 4.5O2

2(C7H9N5O12) → 5N2 + 9H20 + 6CO + 9O2

How does that look?

Offline 408

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Re: A mixture of Nitroglycerin and Ammonium Nitrate produces?
« Reply #2 on: December 15, 2009, 03:02:44 AM »


Different methods exist including Kistiakowsky-Wilson rules, Modified Kistiakowsky-Wilson rules, Springall-Roberts rules.  Just to give you some terms to start searching with.

This paper avoids  fancy math and uses the springall-Roberts rules
http://www3.interscience.wiley.com/journal/112658302/abstract

OK, I am blaming you for interfering with my bedtime, but here are the Springall-Roberts rules

1)carbon is converted to carbon monoxide
2) if any oxygen remains than hydrogen is oxidized to water
3) if any oxygen still remains, than CO is oxidized to CO2
4)All nitrogen is converted to nitrogen gas
5) 1/3 of the CO formed is converted to carbon and carbon dioxide
6) 1/6 of the original amount of CO is converted to form carbon and water.

If this is a question for some sort of school class using these rules may be advanced and they are looking for something simpler for an answer the the question they ask.  If it is just for your own edification:  good for you.

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